如何计算周别

因为要写一个维修生产力的数据录入，数据分析的程序，需要用到周别。但是不知道怎么算，网上的文章好像都不适合；只好自己拍脑袋想了。

每年1/1开始不管第一周满不满7天都算一周。

思路： 找到第一周或者第二周作基准周，然后根据当前日期与基准周的Monday之间的差异天来计算当前的周别。

代码写的简单自己能看懂，好像看的难受，有没有高手有比较简单的方法，谢谢

1.         private void CalWeekNo()
2.         {
   
3.             string base_day, curr_day,base_day_of_week;
4.             DateTime DT_base;
5.             int base_day_of_year,curr_day_of_year;
7.             base_day = “1/1/” + dateTimePicker1.Value.Year;
8.             curr_day = dateTimePicker1.Value.ToString();
10.             DT_base = DateTime.Parse(base_day);
11.             base_day_of_year = DT_base.DayOfYear;
12.             curr_day_of_year = dateTimePicker1.Value.DayOfYear;
13.             base_day_of_week = DT_base.DayOfWeek.ToString();
15.             int day_dif;
16.             day_dif = curr_day_of_year – base_day_of_year;
18.             switch (base_day_of_week)
19.             {
    
20.                 case “Monday”:                    
21.                     weekNo_curr = day_dif / 7 + 1;
22.                     break;
23.            
24.                 case “Tuesday”:
25.                     weekNo_curr = (day_dif+1) / 7 + 1;
26.                     break;
27.            
29.                 case “Wednesday”:
30.                     weekNo_curr = (day_dif + 2) / 7 + 1;
31.                     break;
32.          
33.          
34.                 case “Thursday”:
35.                     weekNo_curr = (day_dif + 3) / 7 + 1;
36.                     break;
37.           
38.                 case “Friday”:
39.                     weekNo_curr = (day_dif + 4) / 7 + 1;
40.                     break;
41.          
42.                 case “Saturday”:
43.                     weekNo_curr = (day_dif + 5) / 7 + 1;
44.                     break;
45.          
46.                 case “Sunday”:
47.                     weekNo_curr = (day_dif + 6) / 7 + 1;
48.                     break;
49.             }
51.            
52.         }